python/nested-lookup
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Fix for issue #10 (#11)

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* Fix for issue #10

* Renamed the test module
This commit is contained in:
Ramesh RV 2018-11-02 21:38:13 +05:30 • committed by Russell Ballestrini
parent 4402da08fe
commit 3441584eaa
3 changed files with 51 additions and 38 deletions
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43
nested_lookup/nested_lookup.py
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@ -49,17 +49,18 @@ def get_all_keys(dictionary):
result_list = []
def recrusion(dictionary):
if hasattr(dictionary, 'items'):
for key, value in iteritems(dictionary):
if isinstance(value, dict):
result_list.append(key)
recrusion(dictionary=value)
elif isinstance(value, list):
result_list.append(key)
for list_items in value:
for key, value in iteritems(dictionary):
if isinstance(value, dict):
result_list.append(key)
recrusion(dictionary=value)
elif isinstance(value, list):
result_list.append(key)
for list_items in value:
# Make sure the items inside the list is iterable
if hasattr(list_items, 'items'):
recrusion(dictionary=list_items)
else:
result_list.append(key)
else:
result_list.append(key)
recrusion(dictionary=dictionary)
return result_list
@ -105,17 +106,19 @@ def _get_occurrence(dictionary, item, keyword):
occurrence = [0]
def recrusion(dictionary):
if hasattr(dictionary, 'items'):
if item == 'key':
occurrence[0] += 1 if dictionary.get(keyword) else 0
elif keyword in dictionary.values():
occurrence[0] += dictionary.values().count(keyword)
for key, value in iteritems(dictionary):
if isinstance(value, dict):
recrusion(dictionary=value)
elif isinstance(value, list):
for list_items in value:
if item == 'key':
occurrence[0] += 1 if dictionary.get(keyword) else 0
elif keyword in dictionary.values():
occurrence[0] += dictionary.values().count(keyword)
for key, value in iteritems(dictionary):
if isinstance(value, dict):
recrusion(dictionary=value)
elif isinstance(value, list):
for list_items in value:
if hasattr(list_items, 'items'):
recrusion(dictionary=list_items)
elif list_items == keyword:
occurrence[0] += 1 if item == 'value' else 0
recrusion(dictionary=dictionary)
return occurrence[0]