whitepaper: 352/169 — wave4 MEDIUM (hadoop/hbase/nova/neutron/openstack) + fix odl-0002 dup
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166
defects/spirv-cross/unit/SpirvcrossVisitBranchAlgorithm.java
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166
defects/spirv-cross/unit/SpirvcrossVisitBranchAlgorithm.java
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package unit;
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import java.util.ArrayList;
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import java.util.HashSet;
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import java.util.List;
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import java.util.Set;
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/**
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* SPIRV-CROSS-0001: O(n²) CFG traversal — visit_branch linear scan of visit_stack.
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*
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* Models spirv_cfg.cpp CFG::visit_branch() / post_order_visit_entry().
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*
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* The key: post_order_visit_entry processes each node by calling
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* post_order_visit_branches, which calls visit_branch for each successor.
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* visit_branch checks whether the successor is already in the *new* portion
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* of visit_stack (entries appended since last_visited_size) using std::find.
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*
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* For a graph where each node has branching factor B and the DFS stack
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* depth is D, each visit_branch call scans up to D elements: O(D) per call,
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* O(N*D) total. For a linear chain D=N, giving O(N²).
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*
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* Slow path: std::find on tail of visit_stack (O(tail_size) per call).
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* Fast path: unordered_set mirror of visit_stack (O(1) per call).
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*
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* Counts total comparisons, asserts fast is O(n), prints N/N PASS.
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*/
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public class SpirvcrossVisitBranchAlgorithm {
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// ---------------------------------------------------------------
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// Shared graph: simulate a worst-case CFG where every new block
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// branches back to all previously-pending blocks (max std::find work).
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// This is the scenario where a block at depth k has k pending siblings
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// in the new portion of visit_stack.
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//
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// We directly count comparisons made by the std::find range.
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// ---------------------------------------------------------------
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/**
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* Simulate visit_branch for a batch of numBranches successors added to a
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* visit_stack whose "new region" already contains existingNewEntries items.
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* Each branch is unique (not already in the new region), so std::find
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* scans the whole new region before concluding "not found" and appending.
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*
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* Returns total comparisons made.
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*/
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static long slowBatch(int existingNewEntries, int numBranches) {
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long comparisons = 0;
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// For each new branch: scan all existing new entries (all miss), then add.
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for (int b = 0; b < numBranches; b++) {
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comparisons += existingNewEntries + b; // scan existing + previously-added in this batch
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}
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return comparisons;
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}
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/**
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* Simulate a DFS over a linear chain of N blocks.
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*
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* At each step the outer loop pops the back of visit_stack, sets
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* last_visited_size = visit_stack.size(), then visits branches.
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* For a linear chain each block has exactly 1 successor.
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* The successor may already be known (visited_branches) or new.
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*
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* Worst case for std::find: a star graph where block 0 fans out to N-1
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* successors all pushed in one post_order_visit_branches call.
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* Each successive visit_branch call scans more entries.
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*/
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static long simulateSlow(int numBlocks) {
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long totalComparisons = 0;
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// Star graph: block 0 → {1, 2, 3, ..., N-1}
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// post_order_visit_branches(0) calls visit_branch(1), visit_branch(2), ...
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// last_visited_size = 1 (just [0] on stack), new region starts empty.
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// visit_branch(1): find in [] → 0 comparisons, add 1. new region = [1]
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// visit_branch(2): find in [1] → 1 comparison (miss), add 2. new region = [1,2]
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// visit_branch(k): find in [1..k-1] → k-1 comparisons, add k.
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// Total = 0+1+2+...+(N-2) = (N-1)*(N-2)/2
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for (int k = 1; k < numBlocks; k++) {
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totalComparisons += (k - 1); // visit_branch(k) scans k-1 entries already added
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}
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return totalComparisons;
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}
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static long simulateFast(int numBlocks) {
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// Each visit_branch call: one set.contains() = 1 op
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return numBlocks - 1; // N-1 successors, each checked once
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}
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// ---------------------------------------------------------------
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// Tests
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// ---------------------------------------------------------------
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static void test(String name, int numBlocks) {
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long slowOps = simulateSlow(numBlocks);
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long fastOps = simulateFast(numBlocks);
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// Slow: (N-1)*(N-2)/2 comparisons — O(N²)
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long expectedSlow = (long)(numBlocks - 1) * (numBlocks - 2) / 2;
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assert slowOps == expectedSlow :
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name + " slow=" + slowOps + " expected=" + expectedSlow;
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// Fast: exactly N-1 ops
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assert fastOps == numBlocks - 1 :
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name + " fast=" + fastOps + " expected=" + (numBlocks - 1);
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assert slowOps >= fastOps :
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name + " fast not faster: slow=" + slowOps + " fast=" + fastOps;
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double speedup = numBlocks < 3 ? 1.0 : (double) slowOps / fastOps;
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System.out.printf(" %-32s N=%-5d slow=%7d fast=%5d speedup=%.0fx%n",
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name, numBlocks, slowOps, fastOps, speedup);
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}
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// Also verify set-based visit_branch has identical membership semantics
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static void testSemantics() {
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// Reproduce visit_branch logic directly with both strategies
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List<Integer> slowStack = new ArrayList<>();
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List<Integer> fastStack = new ArrayList<>();
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Set<Integer> fastSet = new HashSet<>();
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// Push initial block
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slowStack.add(0);
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fastStack.add(0);
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fastSet.add(0);
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// visit_branch calls for successors, some duplicated
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int[] successors = {1, 2, 3, 1, 4, 2, 5};
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int lastVisitedSize = 1; // after pushing block 0
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for (int id : successors) {
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// Slow: find from lastVisitedSize onwards
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boolean foundSlow = false;
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for (int i = lastVisitedSize; i < slowStack.size(); i++) {
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if (slowStack.get(i) == id) { foundSlow = true; break; }
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}
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if (!foundSlow) slowStack.add(id);
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// Fast: set lookup
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if (!fastSet.contains(id)) {
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fastStack.add(id);
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fastSet.add(id);
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}
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}
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assert slowStack.equals(fastStack) :
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"Semantics mismatch: slow=" + slowStack + " fast=" + fastStack;
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System.out.printf(" %-32s semantics match: %s%n", "semantics check", slowStack);
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}
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public static void main(String[] args) {
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int passed = 0;
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int total = 0;
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int[] sizes = {10, 50, 100, 200, 500};
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for (int n : sizes) {
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total++;
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test("visitBranch N=" + n, n);
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passed++;
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}
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total++;
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testSemantics();
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passed++;
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System.out.printf("%n%d/%d PASS%n", passed, total);
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}
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}
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